Interesting value for W, h involving phi,Omega? - Printable Version +- Tetration Forum ( https://math.eretrandre.org/tetrationforum)+-- Forum: Tetration and Related Topics ( https://math.eretrandre.org/tetrationforum/forumdisplay.php?fid=1)+--- Forum: Mathematical and General Discussion ( https://math.eretrandre.org/tetrationforum/forumdisplay.php?fid=3)+--- Thread: Interesting value for W, h involving phi,Omega? ( /showthread.php?tid=110) |

RE: Interesting value for W, h involving phi,Omega? - Ivars - 03/16/2008
Ivars Wrote:I was studying the graph of selfroot of Lambert function: If we use this, we can find : h( (e^(-(e^e)))^e))= h(1,28785E-1 ln((e^(-(e^e))))^e)= e*ln(e^(-e^e)) = -e*e^e so : h( (e^(-(e^e)))^e))= -W(-ln((e^(-(e^e)))^e))/ln((e^(-(e^e)))^e)= -W(e*e^e)/-e*e^e = -e/-e*e^e = 1/e^e= e^(-e) So: h( (e^(-(e^e)))^e))= h(1,28785E-1= e^(-e) = 0,065988036 and second superroot of ((e^(e^e))^e) = ln(((e^(e^e))^e))/W(ln ((e^(e^e))^e)) = e*(e^e)/W(e*(e^e)) = e*(e^e)/e = e^e= 15,15426224 Ssroot( ((e^(e^e))^e)= ssroot(7,76487E+17) = e^e = 15,15426224 For these values, h(1/a) = 1/ssroot(a) I wonder are there any similar relations for W((1/e)*(e^e)) =W(e^(e-1))= W(5.574..) = 1.3894.. Ivars RE: Interesting value for W, h involving phi,Omega? - Ivars - 03/17/2008
Finally I understood defintion of Omega via e secondsuperroot of e : Ssroot (e) = ln(e) / W(ln(e)) = 1/Omega So e= (1/Omega)^(1/Omega) 1/e = (1/Omega)^(-1/Omega) = (Omega)^(1/Omega) Which was known, of course. Ivars RE: Interesting value for W, h involving phi,Omega? - Ivars - 03/27/2008
Sorry Henryk I had to add short version here as it belong Interesting things/ Omega thread if someone is looking here for more interesting values.... I constructed the following function (basically using only real part of module of each iterate) to see what happens when its iterated: Since it is obvious that is the only starting point that will not move since every iteration will return to as argument for and will be next one to converge to after first iteration. So may play a special role in this iterations, and it does.Firstly, all iterations from 1 to pass via this point . Then I found 8500 Excel precision iterates in the region x = ]0.001:0.001:2.71[ (for a starter, it can be done for negative /positive x outside this region as well), via formula: So first conclusion after some numerical modelling and graphing visible in Limit of mean value of iterations of ln(mod(Re(ln(x))) = -Omega constant from all this is : Second, that iterations are bounded with span of values depending on the choice of x steps : size of step and linearity/nonlinearity. Also: Also obviously: for all positive n for all positive n Ivars RE: Interesting value for W, h involving phi,Omega? - Ivars - 04/04/2008
We can create the following expression: |