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sum of log of eigenvalues of Carleman matrix - bo198214 - 08/28/2009
Hey Gottfried, did you notice that the sum over the logarithms of the eigenvalues of the Carleman matrix of exp converge (for increasing matrix size)? Moreover also if you take the n-th power of the logarithms, for any n. This woudl be a direct consequence of the matrix power method (for non-integer iteration of exp) converging to an analytic function. RE: sum of log of eigenvalues of Carleman matrix - Gottfried - 08/28/2009
(08/28/2009, 11:27 AM)bo198214 Wrote: Hey Gottfried,Hmm, for dim=8..24 I get them always near null at machine-precision (Pari/GP, 200digit or 800 digits internal prec). That means the product of the eigenvalues is near 1 no matter what dimension I select. There may be an error, however the procedure is simple. Here is the Pari/Gp code Code: `fmt(800,12)` Wouldn't say, this is exactly convergence with increasing dimension... ;-) Gottfried RE: sum of log of eigenvalues of Carleman matrix - bo198214 - 08/28/2009
Hm, I dont know whether it has a deeper meaning its just an observation RE: sum of log of eigenvalues of Carleman matrix - Gottfried - 08/28/2009
(08/28/2009, 08:58 PM)bo198214 Wrote: Hm, I dont know whether it has a deeper meaning its just an observation Hmm, this means, the determinant of this matrix is 1 for finite dimension - which extends then also for iterates/powers. That the determinant is 1 for finite dimension results also from the determinants of its factors, the stirling- ind the bpascal-matrix. Both are triangular and have units on the diagonal, so det(fS2F) = det(P) = 1 and det(B) = det(fS2F * P~) = det(fS2F)*det(P~) = 1 *1. RE: sum of log of eigenvalues of Carleman matrix - Gottfried - 08/28/2009
(08/28/2009, 09:10 PM)Gottfried Wrote:It is also interesting in contrast to the version, which has the powerseries developed at the first complex fixpoint for exp(x), x0 = 0.318131505205 + 1.33723570143*I .(08/28/2009, 08:58 PM)bo198214 Wrote: Hm, I dont know whether it has a deeper meaning its just an observation With dim=64 I get -at least for the integer iterates -1,1,2 the expected values to 10 digits accuracy - however, the sum of the logarithms of the eigenvalues should be simply, but consequently, log(x0^0) + log(x0^1) + log(x0^2) + ... = log(x0)*(0 + 1 + 2 + 3 + ...) =???= log(x0) * zeta(-1) =-0.0265109587671 - 0.111436308453*I .... well, better not to ride the horse to death... Gottfried |