On replacing 2sinh(2 x) with F(x) ... - Printable Version +- Tetration Forum ( https://math.eretrandre.org/tetrationforum)+-- Forum: Tetration and Related Topics ( https://math.eretrandre.org/tetrationforum/forumdisplay.php?fid=1)+--- Forum: Mathematical and General Discussion ( https://math.eretrandre.org/tetrationforum/forumdisplay.php?fid=3)+--- Thread: On replacing 2sinh(2 x) with F(x) ... ( /showthread.php?tid=774) |

On replacing 2sinh(2 x) with F(x) ... - tommy1729 - 02/20/2013
It came to my mind to replace 2sinh(b x) with another similar realanalytic function F and then perform the same iterations as with the sinh method. The problem is the fixpoints. If I use 2sinh(2 x) to construct a superfunction for exp(2x) then 2sinh(2 L) =/= L. But we have the advantage that 2sinh(2 x) has only one fixpoint so entire iterations for 2sinh(2 x) exists. If however we have F(L)=L then that might make things easier ( analytic continuation ). But there is fear for other fixpoints such as 0 and/or L* resulting in a nonentire and nonunique superfunction of L(x). However if we consider a real superfunction of F(x) and we only have the fixpoints L and L* and both are repelling then it might be intresting to investigate this. Notice here that L and L* means the 2 conjugate fixpoints of the function e^bx. Note however that analytic continuation will still be neccessary. RE: On replacing 2sinh(2 x) with F(x) ... - tommy1729 - 02/20/2013
However I fear such a function does not exist. The reason is F(x) must be so different from exp and sinh. It cannot be of the form exp(x)(x-a)(x-b) and it cannot be of the form exp(x) - exp(ax) - exp(bx). And at the same time F(x) must be entire and have only 2 fixpoints. It seems the Weierstrass factorization theorem implies it must be of a form it cannot be. Also a Dirichlet series for F(x) seems impossible. RE: On replacing 2sinh(2 x) with F(x) ... - tommy1729 - 02/21/2013
I came to realise that I am close to a proof that any formula of the form lim n-> oo ln^[n](f^[x](exp^[n])) for f^[1] entire , cannot be analytic. For certain the probability is at most 1/R where R is the cardinality of the continuum. |