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Incredible reduction for Hyper operators - JmsNxn - 02/13/2014
Hi everyone. I've been doing some exhaustive research into the Weyl differintegral and I've found a very beautiful approach to solving hyperoperators. I'll be very frank. so I'll just state the following results: If Is the Weyl differintegral at zero, then I've shown some equivalencies. If is kosher then it is defined for at least the left half plane ending at the line and as well for all and for and for some Then: As Well we obtain a new expression for which is what I'm going for: I am currently writing a paper on this. The results are solid. I've checked them very well. I can explain how I got to them, but they take a bit to write up. So now we say, by the following. Define the function: where is an entire function of order zero defined by Let us assume there exists an analytic continuation of natural hyperoperators (natural z) for natural values of x (in the first argument), and complex arguments in the second argument (in y). And If and both are kosher then 1/x[z+1]y is kosher and But!!! Since We see we are only talking about the naturals and the results are EQUIVALENT!!!!!!! Okay, I know. This is a big if. Essentially you need to prove that the following integral on the right converges for , that for when and that for some . Where is the following function If this happens and is holomorphic in for all natural . THEN WE HAVE AN ANALYTIC CONTINUATION OF HYPER OPERATORS!!!!!!!!!!!!! QUESTIONS COMMENTS! I have the evaluation that: |