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Infinite tetration and superroot of infinitesimal

No not really shall we give up so fast!

If we have created a hypervolume lets find its hypersurface. Then we can think what it means.

-i^(-1/i) is a new one- but that is the right notation since it takes -i as it is - even better -i^( 1/-i) without doing any simplifications. Really, such small things are important. I try to never simplify an expression too early.

What is the difference between edge and base e^(pi/2)? Andrew mentioned that if e^( pi/2) is one dimensional, it is lenght . Do you think e^(pi/2) is 2 dimensional in some sense, or something else?


Messages In This Thread
RE: Infinite tetration and superroot of infinitesimal - by Ivars - 01/31/2008, 03:56 PM

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