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The balanced hyperop sequence
#7
Oh guys, long time its ago since this thread was started.
But now I am finally able to post the premiere graph of balanced selftetration, i.e. x[4]x where [4] is the balanced tetration.
This was possible by a mixture of recurrent and power series formula.
And this is the result:
   

blue: x[2]x = x*x = x^2
green: x[3]x = x^x
red: x[4]x

Note that 2[n]2 = 4 in balanced hyperoperations of arbitrary rank n.

and here with aspect ratio 1 and the identity in black as comparison, including 0:
   
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Messages In This Thread
The balanced hyperop sequence - by bo198214 - 04/14/2008, 08:44 AM
RE: The balanced hyperop sequence - by andydude - 04/18/2008, 05:23 PM
RE: The balanced hyperop sequence - by bo198214 - 04/18/2008, 05:58 PM
RE: The balanced hyperop sequence - by bo198214 - 04/18/2008, 06:20 PM
RE: The balanced hyperop sequence - by andydude - 04/20/2008, 02:28 AM
RE: The balanced hyperop sequence - by bo198214 - 04/26/2008, 07:20 PM
RE: The balanced hyperop sequence - by bo198214 - 11/30/2009, 11:37 PM

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