Thread Rating:
  • 0 Vote(s) - 0 Average
  • 1
  • 2
  • 3
  • 4
  • 5
Fractals from calculations of 2^I, 2^(2^I), 2^(2^(2^I).. a^(a^(...a^I)
#23
Gottfried Wrote:Infinite product-series can be evaluated by the additive series of their logarithms. In the context of tetration this means, if we get an improvement at all (by this reformulation) then it is only occuring for height 1. For greater heights we are still lost. So everytime this idea pops up in my head, I just dismiss it...

Gottfried

Hmm. But if we have tetration of , then we can continue taking logarithms forever, reducing all heights? No.
Then my beloved just ends where everything else:

(both branches), where is Lambert W function.



So would than divergent products (and even some sums) similarly to divergent tetration end up in complex plane?

Ivars
Reply


Messages In This Thread
RE: Fractals from calculations of 2^I, 2^(2^I), 2^(2^(2^I).. a^(a^(...a^I) - by Ivars - 05/26/2008, 10:30 AM

Possibly Related Threads...
Thread Author Replies Views Last Post
  Different Style of Tetration Fractals stephrenny 5 4,936 12/21/2017, 07:49 AM
Last Post: Gottfried
  Tetrate fractals 73939 0 2,890 07/02/2010, 03:18 PM
Last Post: 73939
  Continuous iteration of fractals Daniel 0 2,815 08/30/2007, 09:55 PM
Last Post: Daniel



Users browsing this thread: 1 Guest(s)