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Additional super exponential condition
#5
I doubt this is an option to extend the mean value operations.
In a given set of data (say a1, a2, ...), ordering is irrelevant for calculating a mean value. But a1^a2(^a3...an) is different from a2^a1(^a3...). Well, at least most of the time.
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RE: Additional super exponential condition - by martin - 10/21/2008, 03:40 PM

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