Infinite Pentation (and x-srt-x)
#15
(04/13/2009, 05:01 PM)bo198214 Wrote:
andydude Wrote:\( \eta < \text{srt}_{k+1}({k+1}) < \text{srt}_k(k) \) for all \( k \ge 5 \) by lemma (4) and lemma (5).
... In the limit, the squeeze theorem and completeness should guarantee that the limit exists and converges to \( \eta \).

Is this right?

I dont think so. When the sequence is decreasing and bounded it has a limit. But this limit could be probably bigger than \( \eta \). Or did I overlook something?

\( \eta < \text{srt}_{k+1}({k+1}) < \text{srt}_k(k) \) for all \( k \ge 5 \)

so the limit must be eta when lim k = oo because the rule is < and not =< , i think bo has overlooked that !?!

or did i miss something ?


Messages In This Thread
Infinite Pentation (and x-srt-x) - by andydude - 04/11/2009, 09:16 AM
RE: Infinite Pentation (and x-srt-x) - by tommy1729 - 05/03/2009, 10:42 PM

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