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Poweroids
#3
(12/18/2009, 08:13 AM)andydude Wrote:
  • forms a poweroid.
...
Andrew Robbins

SCRATCH THAT! it is false.

, but which is not a member of the positive reals. However, with the slight modification
  • forms a poweroid.
I believe the statement is true.

The reason why 0 and 1 must be excluded is so that is uniquely defined. If we include 1, 0 in the base domain, exponent domain respectively, then roots are not uniquely defined, at which point it stops being a poweroid.
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Messages In This Thread
Poweroids - by andydude - 12/18/2009, 08:13 AM
RE: Poweroids - by andydude - 12/19/2009, 10:55 PM
RE: Poweroids - by andydude - 12/19/2009, 11:01 PM



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