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fourier superfunction ?
#3
(06/23/2010, 01:20 AM)mike3 Wrote: can be expressed as a Fourier series, but then how do you express the right hand side? If it's a Taylor series, you can't just equate coefficients, since what they're multiplying is different! E.g. . Just because the coefficients are equal doesn't mean the terms are equal. Equating coefficients of the two distinct series types will not produce a solution of the equation. I don't see what you're trying to get at here...

yes , but the thing is this : we compute the fourier coefficients with the taylor expression and the n'th derivate of the four series.

this crossed self-reference might be solvable directly or recursively.

regards

tommy1729
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Messages In This Thread
fourier superfunction ? - by tommy1729 - 06/22/2010, 10:58 PM
RE: fourier superfunction ? - by mike3 - 06/23/2010, 01:20 AM
RE: fourier superfunction ? - by tommy1729 - 06/23/2010, 10:52 PM

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