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 fourier superfunction ? tommy1729 Ultimate Fellow Posts: 1,358 Threads: 330 Joined: Feb 2009 06/23/2010, 10:52 PM (06/23/2010, 01:20 AM)mike3 Wrote: $f(e^x)$ can be expressed as a Fourier series, but then how do you express the right hand side? If it's a Taylor series, you can't just equate coefficients, since what they're multiplying is different! E.g. $3e^{2x} \ne 3x^2$. Just because the coefficients are equal doesn't mean the terms are equal. Equating coefficients of the two distinct series types will not produce a solution of the equation. I don't see what you're trying to get at here... yes , but the thing is this : we compute the fourier coefficients with the taylor expression and the n'th derivate of the four series. this crossed self-reference might be solvable directly or recursively. regards tommy1729 « Next Oldest | Next Newest »

 Messages In This Thread fourier superfunction ? - by tommy1729 - 06/22/2010, 10:58 PM RE: fourier superfunction ? - by mike3 - 06/23/2010, 01:20 AM RE: fourier superfunction ? - by tommy1729 - 06/23/2010, 10:52 PM

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