closed form for regular superfunction expressed as a periodic function
#17
For the variable-base case,

\( a_n (L \log(B))^n = L \frac{B_n(\log(B), \log(B) 2! a_2, ..., \log(B) n! a_n)}{n!} \)

thus

\( a_n L^{n-1} \log(B)^n n! = B_n(\log(B), \log(B) 2! a_2, ..., \log(B) n! a_n) \)

\( a_n = \frac{B_n(\log(B), \log(B) 2! a_2, ..., \log(B) (n-1)! a_{n-1}, 0)}{(L^{n-1} \log(B)^n - \log(B)) n!} \).


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