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abs f ' (fixpoint) = 0
#3
thanks Bo.

one might wonder why i use abs = 0 instead of 0.

that brings me to the following , suppose im not working with the complex numbers , but some 3d or higher dim numbers that have zero-divisors.

if the fixpoint has f ' ( fix ) = zero-divisor , does boettcher equation still work ?
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Messages In This Thread
abs f ' (fixpoint) = 0 - by tommy1729 - 09/08/2010, 07:59 PM
RE: abs f ' (fixpoint) = 0 - by bo198214 - 09/09/2010, 10:16 AM
RE: abs f ' (fixpoint) = 0 - by tommy1729 - 09/09/2010, 10:13 PM

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