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Imaginary zeros of f(z)= z^(1/z) (real valued solutions f(z)>e^(1/e))
#40
Ivars Wrote:PLEASE post at least one numerical example how to use this limit formula e.f for k=-2, h(e^(pi/2)).

I am not familiar (entirely my fault) with the notations You use - what is n, how to take the limit, what is z, what is b (I assume b=e^(pi/2) in my case.

Yes the notation, mainly you have to know what means, it is simply the times repetition of applied to , for example .

In our example is then . Because we compute which means the complex conjugate of . To compute this we consider and then compute . This can of course only approximately computed. Have a look at some sample values:





But you can see that the value converges, hence .

This is indeed the same value, you get when computing
with Maple.
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Messages In This Thread
RE: Imaginary zeros of f(z)= z^(1/z) (real valued solutions f(z)>e^(1/e)) - by bo198214 - 11/07/2007, 10:26 PM
RE: Tetration below 1 - by Gottfried - 09/09/2007, 07:04 AM
RE: The Complex Lambert-W - by Gottfried - 09/09/2007, 04:54 PM
RE: The Complex Lambert-W - by andydude - 09/10/2007, 06:58 AM

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