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 interpolating the hyper operators JmsNxn Long Time Fellow Posts: 291 Threads: 67 Joined: Dec 2010 06/07/2013, 09:03 PM I realized this is a more efficient way of talking about hyper operators. I will still talk about those $I$ sets, but I think it is a better approach to already have an analytic expression. It came to me in a stroke of luck when I was thinking about fractional derivatives. The goal is to have $f(s) = \frac{1}{x[s]y}$ for all $x,y \in \mathbb{N}$ analytic and entire. The proof of recursion then only revolves around when the output is a natural number. So we only prove for a discrete set of reals. « Next Oldest | Next Newest »

 Messages In This Thread interpolating the hyper operators - by JmsNxn - 05/24/2013, 10:24 PM RE: interpolating the hyper operators - by JmsNxn - 06/07/2013, 05:00 AM RE: interpolating the hyper operators - by MphLee - 06/07/2013, 08:29 AM RE: interpolating the hyper operators - by JmsNxn - 06/07/2013, 09:03 PM

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