Well I have been working on formally justifying this and I have found a way. It's actually a lot like what you said would happen. But it's still quite magical

Suppose f is analytic in the open region G save a finite number of singularities or poles, further more that there exists an antisum for f in G, F such that it is analytic on G save a finite number of poles and singularities and if then

Then, quite beautifully, if is some differentiable arc in G, the following two definitions are equivalent:

if then such that for all there exists an N such that , Then letting

Where this equals:

But by the Mean value theorem where

But this converges to the Riemann integral, since is holomorphic on and is differentiable on :

Therefore!

What does this mean? We can reduce summation to integration! This formula holds for real line calculations. So residues do occur. In fact! if C is some circle around zero in G, then

I've also managed to work out that:

so long as z is in the interior of the contour.

Now to avoid confusion we call these discrete residues. has discrete residues at all negative integers, each equaling This is because

and has poles with residue -2 pi i at negative integers.

Now unfortunately I can't know what to call these points where discrete residues occur. It's a little discouraging, but it's not all because of poles. I think it has more to do with branch cuts. For example:

which gives us some odd behaviour.

I'm currently working on trying to reduce these results to give me a way of calculating infinite sums using discrete residues.

one function I can trivially show it will work on is

We will calculate

knowing that

Take the semi circle consisting of an arc of radius R,A_R and the real line from [-R,R], then is analytic on and furthermore

but it is easy to show: therefore, since and it follows that as

Therefore we are left with only calculating the residues of the poles within the contour, which happen at .

with a little calculation

But using more trivial methods this sum can be easily shown to be zero. It just happens to have a trivial antisum. Calculating antisums into closed form expressions is quite difficult, and so finding discrete residues is a little difficult. I'm working on trying to make this more effable. I'm trying to rigorize my methods of evaluating the antisum using the mellin transform and I've only been able to let it be defined on some strip a < Re z < b

You can begin to see the beautiful applications this should have. I'm still working on investigating this intensely, trying to see if I can find some interesting sums. It's just proving a little laborious to fully justify all this.

Suppose f is analytic in the open region G save a finite number of singularities or poles, further more that there exists an antisum for f in G, F such that it is analytic on G save a finite number of poles and singularities and if then

Then, quite beautifully, if is some differentiable arc in G, the following two definitions are equivalent:

if then such that for all there exists an N such that , Then letting

Where this equals:

But by the Mean value theorem where

But this converges to the Riemann integral, since is holomorphic on and is differentiable on :

Therefore!

What does this mean? We can reduce summation to integration! This formula holds for real line calculations. So residues do occur. In fact! if C is some circle around zero in G, then

I've also managed to work out that:

so long as z is in the interior of the contour.

Now to avoid confusion we call these discrete residues. has discrete residues at all negative integers, each equaling This is because

and has poles with residue -2 pi i at negative integers.

Now unfortunately I can't know what to call these points where discrete residues occur. It's a little discouraging, but it's not all because of poles. I think it has more to do with branch cuts. For example:

which gives us some odd behaviour.

I'm currently working on trying to reduce these results to give me a way of calculating infinite sums using discrete residues.

one function I can trivially show it will work on is

We will calculate

knowing that

Take the semi circle consisting of an arc of radius R,A_R and the real line from [-R,R], then is analytic on and furthermore

but it is easy to show: therefore, since and it follows that as

Therefore we are left with only calculating the residues of the poles within the contour, which happen at .

with a little calculation

But using more trivial methods this sum can be easily shown to be zero. It just happens to have a trivial antisum. Calculating antisums into closed form expressions is quite difficult, and so finding discrete residues is a little difficult. I'm working on trying to make this more effable. I'm trying to rigorize my methods of evaluating the antisum using the mellin transform and I've only been able to let it be defined on some strip a < Re z < b

You can begin to see the beautiful applications this should have. I'm still working on investigating this intensely, trying to see if I can find some interesting sums. It's just proving a little laborious to fully justify all this.