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Taylor polynomial. System of equations for the coefficients.
#16
Here I make an expansion of a row, in hope that it helps somebody to digest the equation.

(01/13/2016, 04:32 AM)marraco Wrote: We are now very close to the solution. The only obstacle remaining is the product:

The product is what I called "the integer divisor"

(05/03/2015, 04:35 AM)marraco Wrote:




^^ Here I expanded the row for i=9 of the equation:




after the substitution :


The problematic terms come from the factors . The q! divisors may emerge not from the term raised to q. q! could emerge from the absence of the other terms: .
For example, the term is actually

I have the result, but I do not yet know how to get it.
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