05/14/2015, 08:58 PM

That is not consistent with the many singularities ...

Unless you take your slog branches different ?!

If you take your branches perpendicular to the real axis instead of parallel.

However , are we really Free to choose our branch cuts ?

Afterall we need the equality exp^[1/2](z) = sexp(slog(z)+1/2) to hold.

Regards

Tommy1729

Unless you take your slog branches different ?!

If you take your branches perpendicular to the real axis instead of parallel.

However , are we really Free to choose our branch cuts ?

Afterall we need the equality exp^[1/2](z) = sexp(slog(z)+1/2) to hold.

Regards

Tommy1729