11/24/2015, 07:16 AM
(11/24/2015, 02:56 AM)Gottfried Wrote: Did you see already whether it is possibly simply extensible to higher orders?
Gottfried
I tried doing something similar with superroot-4, but no luck, however, I found the coefficients by solving the equation
\( \exp_{\exp(u)}^{3}(z) = \exp(v) \)
so you should be able to add \( z^j \) to the above formula to solve this generalization. The above formula is just the special case when \( z=1 \).