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How about ... F(x)^[3] + 2 F(x)^[2] = exp(x) ?
#1
How about ... F(x)^[3] + 2 F(x)^[2] = exp(x) ?

I have no idea how to do this.

This bugs me. Its a simple equation.

Regards

Tommy1729
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#2
It seems logical to consider F_{n+1}(x) = ( 1/2 ( exp(x) - f_{n}^[3](x) ) )^[1/2].


The limit of the iteration is then the solution.

But how about convergeance and analyticity ?


Regards

Tommy1729
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#3
Maybe start the iteration with exp^[1/3](x).

Regards

Tommy1729
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