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 Inverse super-composition Xorter Junior Fellow Posts: 46 Threads: 14 Joined: Aug 2016 01/12/2017, 04:19 PM Okey, I have found something looking like the solution. I feel I am closer than ever before. For the following functional equation $2x ^{oN} = exp(x)$ my method gives: $N = 0.5250548915-0.2859572213x+0.3455886342x^2-0.0759083804x^3+0.0201418181x^4-0.0045151851x^5+0.0006517298x^6+...$ Let us check it: $2x ^{o0.5250548915-0.2859572213x+0.3455886342x^2-0.0759083804x^3+0.0201418181x^4-0.0045151851x^5+0.0006517298x^6+...}$ looks like sg like the exoponential function. Of course, because at x=0 exp x = 1, then x2^n will never go up to 1, so in the reals there is no more beautiful solution for N like mine, I think or I am wrong, ain't I? What do you think, is this function correct? Or is there better? Xorter Unizo « Next Oldest | Next Newest »

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