01/12/2017, 04:19 PM

Okey, I have found something looking like the solution. I feel I am closer than ever before.

For the following functional equation

my method gives:

Let us check it:

looks like sg like the exoponential function.

Of course, because at x=0 exp x = 1, then x2^n will never go up to 1, so in the reals there is no more beautiful solution for N like mine, I think or I am wrong, ain't I?

What do you think, is this function correct? Or is there better?

For the following functional equation

my method gives:

Let us check it:

looks like sg like the exoponential function.

Of course, because at x=0 exp x = 1, then x2^n will never go up to 1, so in the reals there is no more beautiful solution for N like mine, I think or I am wrong, ain't I?

What do you think, is this function correct? Or is there better?

Xorter Unizo