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02/03/2008, 04:40 PM
(This post was last modified: 02/03/2008, 07:40 PM by Ivars.)
I was strugling to get in grips with infinite pentation of other base than e but failed.
So my question to experts:
Which y would satisfy the equation in the subject of the thread?
My guess is e^(-pi), so that:
e^(pi/2) [5] ( - infinity) = e^(-pi).
Ivars
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Thank you, Ivars. Let us see.
@ Andydude.
Could you please check the coordinates of the common intersection, for x < 0, and for b = e^(Pi/2), with your powerful slog and sexp machines, of:
- y = b # x = b-tetra-x;
- y = [base b]slog x, the inverse of the previous one;
- y = x, principal diagonal ?
The intersections of the three "tails" for x < 0 should correspond to b-penta(-oo).
But, I might be wrong.
GFR
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Is this very difficult or not interesting?
I still have not acquired software to be able to do it myself one day. I will proceed analytically, but that might take years
Ivars
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02/26/2008, 10:45 AM
(This post was last modified: 02/26/2008, 10:54 AM by bo198214.)
Ivars Wrote:Is this very difficult or not interesting?
The value must be somewhere around -2 (far from your guess of

) considering this picture showing the intersection of

with

.
I guess it is not symboblically expressable with

,

and

.
But it is not exactly -2, because
 > -2)
for all real

.
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Thanks!
Seems rather symmetrical, this value.
Ivars