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 The super 0th root and a new rule of tetration? Xorter Fellow Posts: 93 Threads: 30 Joined: Aug 2016 11/27/2017, 01:44 PM Hi, everyone! I have been working on the so-called iterated analysis. And I have found an interesting formula in that I am not so sure, so I share it with you to discuss it. So, what if I say: lim h->infinity super 1/h-th root of ( (f^^N)-th root of f^^N ) = lim h->infinity (super 1/h-th root of ((f)-th root of f))^^N which is equivalent to super 0th root of ( (f^^N)-th root of f^^N ) = (super 0th root of ((f)-th root of f))^^N 1st question: How can we calculate the super 0th root of a number or a function? Any idea? Xorter Unizo « Next Oldest | Next Newest »

 Messages In This Thread The super 0th root and a new rule of tetration? - by Xorter - 11/27/2017, 01:44 PM RE: The super 0th root and a new rule of tetration? - by Xorter - 11/27/2017, 06:33 PM RE: The super 0th root and a new rule of tetration? - by sheldonison - 11/28/2017, 04:15 PM RE: The super 0th root and a new rule of tetration? - by Xorter - 11/28/2017, 05:45 PM RE: The super 0th root and a new rule of tetration? - by Xorter - 11/29/2017, 11:53 AM

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