03/23/2015, 02:31 PM
(03/23/2015, 01:39 PM)marraco Wrote:Ure misunderstanding the expression(03/21/2015, 11:11 PM)tommy1729 Wrote: a*b = b*aThat would mean
"add+b"^[a-1](1*b) = "add+a"^[b-1](1*a)
b*(a-1)=a*(b-1)
but if "-" is an inverse operator of [q], such that x-y is defined as x-y=x[q]-y, and -y is defined as y[q]-y=N(q,y) then
for [q]=product, "-" would be division, so
In fact Tommy tryes to replace g and f with "add_b" and "add_1" and the interpretation becomes the following
Quote:General case
- Case q=1 with
- Case q=2 with
- Case q=0 with
Quote:-∞ is used on all the basic operations:Agree with this last point...
the neutral of addition is ÷∞=1/∞=0
the neutral of product is ∞√=∞√n=n^÷∞=1
the neutral of exponentiation is
from product viewpoint, all numbers smaller than 0 are transfinite.
from exponentiation of n viewpoint, all numbers smaller than 1 are transfinite.
from tetration of n viewpoint, all numbers smaller thanare transfinite.
It really deserves some attention imho.
MathStackExchange account:MphLee