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 Math.Stackexchange.com question on extending tetration Daniel Fellow Posts: 141 Threads: 47 Joined: Aug 2007 03/28/2021, 06:26 AM Howdy, Check out a question on extending tetration. I'm inviting folks to critic my answers or to provide your own. Daniel JmsNxn Ultimate Fellow Posts: 772 Threads: 105 Joined: Dec 2010 03/29/2021, 02:11 AM I liked that post. Cool graphics, it's nice to see some love for the standard iteration--and a cool Taylor Series for it. nuninho1980 Fellow Posts: 96 Threads: 6 Joined: Apr 2009 03/30/2021, 03:24 PM (This post was last modified: 03/30/2021, 03:56 PM by nuninho1980.) (03/28/2021, 06:26 AM)Daniel Wrote: Howdy, Check out a question on extending tetration. I'm inviting folks to critic my answers or to provide your own. Daniel I use Maple 2020. base^^x = f(x) = lim n -> infinity (log_base[n](1 - ln(W(-ln(base))/(-ln(base)))^x)*W(-ln(base))/(-ln(base)) + ln(W(-ln(base))/(-ln(base)))*exp_base[n](1))) --> Is this formula correct? But... On Maple -- n = 10 times: - input --------------------------------------------------------------------------------------------------------------------------- Digits:=20: base:=1.35: x:=2.: log[base](log[base](log[base](log[base](log[base](log[base](log[base](log[base](log[base](log[base]((1 - ln(LambertW(-ln(base))/(-ln(base)))^x)*LambertW(-ln(base))/(-ln(base)) + ln(LambertW(-ln(base))/(-ln(base)))*base^(base^(base^(base^(base^(base^(base^(base^(base^(base^base))))))))))))))))))); --------------------------------------------------------------------------------------------------------------------------- - output -------------------------------- 5.8512341052940943912 -------------------------------- --> This output is incorrect... 1.35^^2 = 1.4995142162286330979 --> this is correct. JmsNxn Ultimate Fellow Posts: 772 Threads: 105 Joined: Dec 2010 03/31/2021, 12:28 AM (This post was last modified: 03/31/2021, 12:29 AM by JmsNxn.) Hey, nuninho1980. I'd take everything Anixx posts with a grain of salt. I can vouch for the Newton series he gives, but not the weird Lambert limit. I'm not sure how he's getting that, lol. The Newton series does converge very very slow though, so his method may have just as slow convergence. Regards, James « Next Oldest | Next Newest »

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