I suppose it goes without mentioning that you simply reverse the process to take logarithms of very large numbers.
)\\<br />
\begin{eqnarray}<br />
\text{Then }\log_c(\log_c(a^x)) & = & c^{z}+\log_c(\log_c{a}))<br />
\end{eqnarray}<br />
)
which entails:
)\\<br />
\begin{eqnarray}<br />
\text{Then }\log_c(\log_c(\log_b(b^x))) & = & \log_c(w-\log_c(\log_c{b}))<br />
\end{eqnarray}<br />
)
Here we see the tools to iteratively exponentiate in base a, then iteratively take logarithms in base b.
which entails:
Here we see the tools to iteratively exponentiate in base a, then iteratively take logarithms in base b.
~ Jay Daniel Fox