TPID 6 Catullus Fellow Posts: 213 Threads: 47 Joined: Jun 2022   07/03/2022, 09:39 AM (This post was last modified: 07/03/2022, 10:08 AM by Catullus.) (05/01/2009, 09:20 AM)bo198214 Wrote: For a discussion of the topic see http://math.eretrandre.org/tetrationforum/showthread.php?tid=198&pid=2411#pid2411 Conjecture Let $b=\sqrt{2}$. Every real function $f$ on $(-2,\infty)$ that satisfies: $f(0)=1$ $f(x+1)=b^{f(x)}$ $f(-f(x))=-x$ is not continuous at any point..If I click on the link to that thread it says "The specified thread does not exist.". Why did that happen? Please remember to stay hydrated. ฅ(ﾐ⚈ ﻌ ⚈ﾐ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\ tommy1729 Ultimate Fellow Posts: 1,859 Threads: 402 Joined: Feb 2009 07/04/2022, 12:55 PM (07/03/2022, 09:39 AM)Catullus Wrote: (05/01/2009, 09:20 AM)bo198214 Wrote: For a discussion of the topic see http://math.eretrandre.org/tetrationforum/showthread.php?tid=198&pid=2411#pid2411 Conjecture Let $b=\sqrt{2}$. Every real function $f$ on $(-2,\infty)$ that satisfies: $f(0)=1$ $f(x+1)=b^{f(x)}$ $f(-f(x))=-x$ is not continuous at any point..If I click on the link to that thread it says "The specified thread does not exist.". Why did that happen? Yes i confirm these missing or dead links that Cattulus points out ! Are they accidentally in hyperoperations ?  I cannot find certain posts anymore and I take that serious ! regards tommy1729 « Next Oldest | Next Newest »

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