A Limit Involving 2sinh
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Question 
Please let [Image: png.image?\dpi%7B110%7D%20f(x)] equal [Image: png.image?\dpi%7B110%7D%20g%5Ex(1)], where [Image: png.image?\dpi%7B110%7D%20g(x)=2*\sinh(x*\ln2)=2%5Ex-2%5E%7B-x].
Then, what is [Image: png.image?\dpi%7B110%7D%20\lim_%7Bx\to\infty%7Df...row%20x)-x]?
Isn't the 2sinh function great!?
Please remember to stay hydrated.
ฅ(ミ⚈ ﻌ ⚈ミ)ฅ Sincerely: Catullus /ᐠ_ ꞈ _ᐟ\
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