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Fractals from calculations of 2^I, 2^(2^I), 2^(2^(2^I).. a^(a^(...a^I)
#27
I corrected the mistakes of taking logarithms from h(z) in previous posts.

But one could still ask if there exists transformation H such that :



Then

would always be a divergent sum, related to h(z). Instead of all z being similar, one can have e.g z=2^n or other general term, then these sums will coincide with usually known divergent sums like 1+2+4+8+16+32........ or 1+1+1+1+1+1....

Similarly 1/h(z) could be transformed in z/z/z/z/z/z/z.......... and sums would be -z-z-z-z-z-z-...?

Ivars
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RE: Fractals from calculations of 2^I, 2^(2^I), 2^(2^(2^I).. a^(a^(...a^I) - by Ivars - 05/27/2008, 11:45 AM

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