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matrix function like iteration without power series expansion
#2
Using a matrix-expression this would be

t°h(x) = W^-1 sum k=0..inf sum j=0..k (-1)^j * binomial(k,j) *diag(1,u^j,u^2j,...) * W

sum j=0..k (-1)^j * binomial(k,j) *dV(u^j) = diag(u^j-1) *PPow(
sum k=0..inf
bo198214 Wrote:

Notes:
  1. Perhaps Gottfried can jump in to provide summability in the divergent case .

Hmm, let me try (maybe I didn't get this right yet).


is

which is just a binomial weighting of the coefficients c_n.

In my analyses I got the coefficients



so, for instance, the c_n for the half-iteration are



The rate of growth of the a_n-coefficients for t=0.5 was asymptotically



where m_n are also growing coefficients, if only the leading coefficient
of the polynomials at x^n are taken into account.
Now the quotient of two consecutive binomials



seem to approach -1, so the strong growth of about u^n^2/n!, or the
quotient of two consecutive coefficients of ~ u^2n/n seems to
dominate the characteristic of the c_n-coefficients.

A series with quotient of increasing absolute value u^(2n)/n, u>1 cannot
regularly be Euler-summed; maybe it can be summed with Borel-summation of
higher orders.

To be "not regularly" Euler-summable does not mean, we cannot have
an approximation of a certain degree; however the problem with
this is, that the partial sums may converge up to a certain
index n, from where it "begins to diverge" - and it is not yet
known to me, to what extent we can use the intermediate approximated
value - I'm investigating for verification of some experimental
summation-methods of the required power.

Hmm - i hope this is not more confusing than clarifying - I've my
head not really free today (have to prepare the final lesson tomorrow)

Gottfried
Gottfried Helms, Kassel
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Messages In This Thread
RE: matrix function like iteration without power series expansion - by Gottfried - 06/30/2008, 09:23 PM

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