07/15/2008, 11:40 AM

I know, I said this formula works for 0 < x < 1, the other values are naturally obtained

- for x<0 by iterated log[2^^(x+1)]/log(2)

- for x>1 by iterated 2^(x-1)

I just wanted to know if this is a way to obtain the values for non-integer x.

Thanks,

Martin

- for x<0 by iterated log[2^^(x+1)]/log(2)

- for x>1 by iterated 2^(x-1)

I just wanted to know if this is a way to obtain the values for non-integer x.

Thanks,

Martin