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Just asking...
#17
andydude Wrote:http://tetration.itgo.com/newtxt/table-tetbin.txt

Wow, that's an extensive and interesting table. I especially like the values below -2.


Ivars Wrote:If in series there is 1/n!, then formula becomes:
n= ln(2) * ((1-exp(-x))/x)

if just 1/n, then:
n= ln(2) * (ln(1+x)/x)

Nope, neither of them worked. But hey, it was worth trying.

Meanwhile, I figured out linear parameters for 3^^x.
With n = 0.0813-0.328823x, for 0 < x < 1: 3^^x ~~ [x(3^n-1)+1]^(1/n)
Again, quite close, but still with minimal irregularities.
Either I didn't try long enough to find exact parameters, or I'm really on the wrong track. (Most probably the latter. (Then again, thinking about n to be a polynomial of infinite degree or some other equation ... nah, I leave that to someone else who's interested.))
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Messages In This Thread
Just asking... - by martin - 07/14/2008, 09:49 PM
RE: Just asking... - by bo198214 - 07/14/2008, 10:53 PM
RE: Just asking... - by martin - 07/15/2008, 11:40 AM
RE: Just asking... - by bo198214 - 07/16/2008, 08:00 PM
RE: Just asking... - by martin - 07/16/2008, 09:52 PM
RE: Just asking... - by bo198214 - 07/16/2008, 10:36 PM
RE: Just asking... - by bo198214 - 07/16/2008, 10:52 PM
RE: Just asking... - by martin - 07/17/2008, 11:28 AM
RE: Just asking... - by bo198214 - 07/18/2008, 01:48 PM
RE: Just asking... - by martin - 07/18/2008, 06:37 PM
RE: Just asking... - by bo198214 - 07/18/2008, 10:02 PM
RE: Just asking... - by Gottfried - 07/19/2008, 03:48 AM
RE: Just asking... - by Ivars - 07/19/2008, 07:04 AM
RE: Just asking... - by martin - 07/19/2008, 09:03 AM
RE: Just asking... - by Ivars - 07/19/2008, 07:45 PM
RE: Just asking... - by andydude - 07/21/2008, 04:05 AM
RE: Just asking... - by martin - 07/21/2008, 06:31 PM
RE: Just asking... - by Ivars - 07/22/2008, 06:07 AM



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