exponential polynomial interpolation

[Gottfried]

Fiddling with alternate interpolation-approaches I came to an interpolation-technique, which is not "alternate" in the sense as I was searching, but has some interesting aspect on its own.

It also seems to back the diagonalization-method from another point of view.

I've not seen this before (nor in a more common serial representation) - may be someone recognizes it though I used the matrix-notation.

It is at
http://go.helms-net.de/math/tetdocs/Expo...lation.pdf

and -if of interest here- I'd upload it to the forum-resources.

Gottfried

[andydude]

There is a recurrence equation for hyperbolic iteration that Henryk describes here, and I later noticed here and since this is a "finite" recurrence equation, everything is eventually defined in terms of , which is equivalent to your in the case . I have also noticed that you can better describe hyperbolic iteration as a polynomial in , but I have yet to find any patterns of note. Henryk's recurrence equation for hyperbolic iteration seems to be a great resource for explaining how and why it works the way it does.

Andrew Robbins

[Gottfried]

There is a recurrence equation for hyperbolic iteration that Henryk describes here, and I later noticed here and since this is a "finite" recurrence equation, everything is eventually defined in terms of , which is equivalent to your in the case .

Hi Andrew -
thanks for the hint; I just reread that. I'll try to translate this into my matrix-lingo and see, how it is related. Though my Eigensytem-solver does not require the iterates g = f°t I think the interpolation-approach may be related to it this way.

I have also noticed that you can better describe hyperbolic iteration as a polynomial in , but I have yet to find any patterns of note.

Do you remember my diagonalization formula? (pg 21 in
"ContinuousFunctionalIteration"

Gottfried

[andydude]

First, I think you meant ContinuousfunctionalIteration (your URL was broken). Second, I think that actually . Yes, I remember your U-tetration formula... I think you've found the most patterns in that so far...

Andrew Robbins