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 Taylor series of upx function bo198214 Administrator Posts: 1,389 Threads: 90 Joined: Aug 2007 11/16/2008, 07:17 PM (This post was last modified: 11/16/2008, 07:21 PM by bo198214.) Kouznetsov Wrote:There is EXACT Tailor series, if we insist that upx(z^*) = upx(z)^* and upx(z) is holomorphic outside the part of the negative part of axis, id est, holomorphic everywhere except $z\le 2$. Then the solution is unique. Dmitrii, that is not yet proven. Even with what you call lemma about almost identical functions, we still need conditions for the slog, to make something unique here. I do not yet see a uniqueness criterion that does not depend on the shape of $\text{upx}(S)$. We have to make a waterproof proof before announcing something wrong! See my thread Universal Uniqueness Criterion II about what we really have in the moment. « Next Oldest | Next Newest »

 Messages In This Thread Taylor series of upx function - by Zagreus - 09/07/2008, 10:56 AM RE: Taylor series of upx function - by bo198214 - 09/10/2008, 01:56 PM RE: Taylor series of upx function - by andydude - 10/23/2008, 10:16 PM RE: Taylor series of upx function - by Kouznetsov - 11/16/2008, 01:40 PM RE: Taylor series of upx function - by bo198214 - 11/16/2008, 07:17 PM RE: Taylor series of upx function - by sheldonison - 11/17/2008, 12:21 AM RE: Taylor series of upx function - by Kouznetsov - 11/17/2008, 04:11 AM RE: Taylor series of upx function - by bo198214 - 11/18/2008, 11:49 AM RE: Taylor series of upx function - by sheldonison - 03/05/2009, 06:48 PM RE: Taylor series of upx function - by Kouznetsov - 12/02/2008, 12:03 PM RE: Taylor series of upx function - by sheldonison - 12/03/2008, 09:11 PM RE: Taylor series of upx function - by Kouznetsov - 12/05/2008, 12:30 AM

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