05/23/2008, 04:35 PM

bo198214 Wrote:Bo, namely for my expression can be simplified to yours.Quote:No, that does not. The analytic tetrations should coincide. Does your soluiton show periodHm, not exactly, what I derived some posts earlier would give merely , yours is .

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Quote:Btw. there are infinitely many analytic functions that have no singularity on right halfplane: If has no singularity there, also , , is a superexponential with no singularities on the right halfplane and any 1-periodic function with in would do.I disagree. At some smooth contour in your strip, the contour enters the left halfplane and crosses the cut . You have no need to evaluate any tetration in order to see it. Corresponding contour is not continuous.

Fig.2 is ready at

http://en.citizendium.org/wiki/Tetration...rameters00. Try to run it.