04/06/2009, 10:49 PM
nuninho1980 Wrote:now the fixed point more smooth
1.6353244967 ^^^ oo ~= 3.0885549441 (200 dimensions of matrix)
b ^^^ oo = x => slog_b (y) = x, y=x, if b<=1.6353244967 and b=/=1.6353244968 then x<y and x>y.
Oh, you mean we have an upper fixed point of the tetrational for
Of course there maybe always the dependency of the values from the chosen method of tetration.
Quote:"tetration and slog" original by Andrew Robbins is as smoother as "new regular slog"
So how big is the difference between both methods, with respect to the computed fixed point?