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05/11/2009, 09:31 PM
(This post was last modified: 05/11/2009, 09:32 PM by bo198214.)
(05/11/2009, 09:12 PM)BenStandeven Wrote: Actually, , so they are translations of each other, albeit along the imaginary axis instead of the real axis.
Well observed! So this is not even the worst nonuniqueness.
This is generally the case, that there are these two regular superfunctions at a fixed point. And one is the other translated by some imaginary value (up to real translations along ) which is half of the period of both functions.
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(04/29/2009, 06:59 PM)bo198214 Wrote: Ansus Wrote:I've verified both and both indeed correct solutions. Mathematica finds for the general case of .
What Maple gives for ?
Nothing
hasnt this been solved before ?
regarding my critisism ( in a previous post in this thread ) that only ( elementary or other ) superfunctions of polynomials , a x ^ b or moebius functions are known ;
a challange :
what is the superfunction of
(a x ^ 2 + b x + c) / ( A x^2 + B x + C )
( yes, it can in some cases be reduced , common factors divided away , different cases occur ( different amount and position of fixpoints ) , i know that ... )
i sometimes call this superfunction " generalized sine / cosine "
( on sci.math e.g. )
regards
tommy1729
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07/16/2009, 04:42 AM
(This post was last modified: 07/17/2009, 09:49 AM by Kouznetsov.)
(05/11/2009, 07:39 PM)bo198214 Wrote: (05/11/2009, 05:17 PM)Ansus Wrote: It should be noted that superfunction is not unique in most cases. For example, for
, superfunction is
Ya, this is the simple kind of nonuniqueness, its just a translation along the xaxis.
However there are also more severe types of nonuniques, as I already introduced in my first post, we have two solutions (which are not translations of each other):
and .
1. Sorry, Henryk, they are translations of each other.
.
We already had similar discussion with respect to tetration on base ,
http://www.ils.uec.ac.jp/~dima/PAPERS/2009sqrt2.pdf , figure 3.
the growing up SuperExponential (red) and the tetration (blue), at the appropriate translations formula (5.7) and formula (5. become very similar and bounded along the real axis functions (green). (I do not know why the number of forumla that follows (5.7) becomes some strange "smile". I mean just the number of formula, nothing more.)
2. There are many ways to extend the table of superfunctions.
I suggest the group of transforms of the pairs (TransferFunciton, SuperFunctions).
<b>Theorem</b>.
Let ,
Let ,
Let ,
Let .
Then .
Proof:
(end of proof).
With transform , from the pair (f,F) we get the pair (h,E).
2.1. Also, in the right hand side of the expression
we can swap and ;
this gives the new transfer function
with known superfunction .
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03/27/2010, 10:27 PM
(This post was last modified: 03/27/2010, 10:44 PM by bo198214.)
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04/18/2010, 01:17 PM
(This post was last modified: 04/18/2010, 01:19 PM by bo198214.)
Did we mention already the tangent? It has this nice addition theorem:
which brings us the superfunction:
for the function
is another particular case of a linear fraction (where the regular iteration at both fixed points coincide).
The two (nonreal) fixed points are:
,
for
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Another one:
has two fixed points with the derivations:
and
.
The above superfunction is the regular iteration at the upper fixed point
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04/25/2010, 09:23 AM
(This post was last modified: 04/25/2010, 09:43 AM by bo198214.)
(04/25/2010, 09:11 AM)Kouznetsov Wrote: Henryk, it seems to me that such a case can be obtained from the example 5 of the Table 1 of our article
Yes that is right, is polynomially conjugated to , i.e. there exists a polynomial such that , and as we know a superfunction of is , we know that a superfunction of is .
But we dont have a decision criteria when a given polynomial is conjugated to some .
Particularly all polynomials without real fixed point, e.g. , seem not be (real) conjugated to some .
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Challenge:
Is there an elementary superfunction of a polynomial that has no real fixed point?
