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Andrew Robbins' Tetration Extension
#14
bo198214 Wrote:So what do you actually prove?

That:
(expanded about z=0) and:
(expanded about z=0),
which means in the limit:

and:


One of the nice things about having an exact form for all approximations is that the approximations are invertible (so we can find tetration as well) but the limit to infinity makes it discontinuous, which is not invertible.

Andrew Robbins
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Messages In This Thread
Andrew Robbins' Tetration Extension - by bo198214 - 08/07/2007, 04:38 PM
RE: Andrew Robbins' Tetration Extension - by andydude - 11/13/2007, 12:16 AM

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