11/13/2007, 05:45 PM

Indeed, that would be strange. I'm not assuming convergence, but I am assuming that:

What I can prove is that for the nth approximation of the super-log (the finite series):

From this it is easy to show

Andrew Robbins

- convergence of the finite series (approximations with coefficient approximations as well) to the infinite series, or in other words: where or in other words: , and

- convergence of the infinite series (whose coefficients must also converge), or in other words:

What I can prove is that for the nth approximation of the super-log (the finite series):

- As , with n+1 entries.

- As , with k = 0 .. n.

From this it is easy to show

Andrew Robbins