08/11/2009, 02:14 AM
(This post was last modified: 08/11/2009, 02:26 AM by Base-Acid Tetration.)
andydude Wrote:Actually, it is a prefixno, -iter- is not a prefix, it's a word-stem of latin that means repeating.
but i have no problem adopting it as a prefix. it's clearer than "super".
(08/11/2009, 12:06 AM)bo198214 Wrote: So guys,
to solve our current problems, I come up with the following quite memorizable and hopefully non-confusing suggestion:
Roughly:
An-exponential
is the
times application of
to
.
An-logarithm
returns the number
of iterations of
necessary to be applied on
to obtain
.
Additionally we may also have:
An-power
is the
times application of
to
(same as
-exponential but function in
, not in
.)
Implicitely there is contained the concept of the Abel function:is an Abel function for each
and that of a superfunction/iterational
is a superfunction for each
.
Also ability to specify an initial valueon which the iterations are applied, was often asked for here on the forum.
Another thing is that imho it lets one think more in the direction of "a"-exponential, while the prefix "super" rather suggests "the" superfunction, super-exponential.
"is an
-exponential". (How do the native speakers think about it?)
So we can leave the old super-notation in there previous meaning (though I think it is an unnecessary notation as everything can be specified with tetra-, penta-, etc. prefixes.)
it will be confusing w/ my greek prefix terminology (tetra-, etc.). is a tetra-exponential an iterate of tetration b[4]x, as your terminology would suggest, or is it an iteration of b^x?
but you don't need to worry about english, i thought you were a native speaker the first time i was here, i never knew you were henrik trappmann, a guy in germany
