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 proof: Limit of self-super-roots is e^1/e. TPID 6 Base-Acid Tetration Fellow Posts: 94 Threads: 15 Joined: Apr 2009 07/10/2010, 05:19 AM (This post was last modified: 07/10/2010, 05:32 AM by Base-Acid Tetration.) The same method of proof could possibly be used to easily prove that, possibly for all k>4, limit of self-hyper-k-root(x) as x -> infinity = $\eta_k$ (defined as the largest real x such that $x[k]\infty < \infty$, i.e. where the maximum of self-hyper-(k-1)-root function occurs; let's establish this notation); yeah I know, I only substituted the pentation-analogues into the proof and quickly checked. « Next Oldest | Next Newest »

 Messages In This Thread proof: Limit of self-super-roots is e^1/e. TPID 6 - by bo198214 - 10/07/2009, 08:00 AM RE: proof: Limit of self-super-roots is e^1/e. TPID 6 - by andydude - 10/07/2009, 09:52 PM RE: proof: Limit of self-super-roots is e^1/e. TPID 6 - by Base-Acid Tetration - 07/10/2010, 05:19 AM RE: proof: Limit of self-super-roots is e^1/e. TPID 6 - by bo198214 - 07/10/2010, 09:13 AM

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