12/19/2009, 05:06 AM
Another use for this formula is that it converges very rapidly even if f(x) does not converge quickly to its fixed point.
For example I computed \( {}^{1/2} (e^{1/e}) \) using 10 iterations and got 1.257153126 which should be good to 7 decimal places. (using 11 iterations I get 1.257153143)
Thanks
For example I computed \( {}^{1/2} (e^{1/e}) \) using 10 iterations and got 1.257153126 which should be good to 7 decimal places. (using 11 iterations I get 1.257153143)
Thanks