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Equations for Kneser sexp algorithm
#16
(06/14/2011, 03:00 PM)sheldonison Wrote: Its definitely a uniqueness criterion. Another way to think about it is from the point of view that is connected to Kneser's unique Riemann mapping, since . But yes, any sexp(z) solution would either be the unique solution, with exponentially decaying to a constant as , or else if it is any other solution, than grows exponentially as .

That screams for a proof, does it?
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RE: Equations for Kneser sexp algorithm - by bo198214 - 06/14/2011, 05:07 PM

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