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about kouznetsov again
#1
about kouznetsov's tetration.

lim b -> oo f(a + bi) = fixpoint exp.

that seems true for integer a and integer b but is that true for all real a and b ?

it was said to be periodic , so i guess not.

but is it bounded ? it seems like a double periodic limit at oo then.

in general double periodic is unbounded in its period ...

but this is a special case ; approaching at oo.

the cauchy contour would work better if we truely had :

lim b -> oo f(a + bi) = fixpoint exp.

that would require that f(x + i) = g(f(x)) and g(x) has fix exp as a strong and unique fixpoint ( i think ).

in that case the cauchy contour should work better ! not ?

but how to construct such a solution ?

this related to another recent post i made : " twice a superfunction ".

regards

tommy1729
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#2
(08/12/2010, 12:26 PM)tommy1729 Wrote: about kouznetsov's tetration.

lim b -> oo f(a + bi) = fixpoint exp.

that seems true for integer a and integer b but is that true for all real a and b ?

it was said to be periodic , so i guess not.

It's true for all real a. b isn't free in that formula; the limit does not depend on how b approaches oo. Of course, this only works for bases greater than eta; below that the tetration function would be periodic, as you point out.
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