Ivars Wrote:next ln2+ ln*lnGamma(1/2) - lnln2 etc. ln2 and lnln2 will cancel out, so

in the end we will have lnln............ln (Gamma(1/2) when n-> infinity.

Actually it does not matter with which value (instead of -1) you start the iterations of as long as you dont take some hyperpowers of for example would lead to 0 after 4 times application of the and taking again would give , so the formula would not work with this starting value.