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Tetration of 2 and Aleph_0
#3
VERY controversial subject.

many flamewars going on about this.

my opinion is this

2^^aleph_0 = aleph_aleph_0

and further

2^(aleph_aleph_0) = aleph_aleph_0

notice aleph_0 + 1 = aleph_0

and 2^^(aleph_aleph_0) = aleph_aleph_0

notice 2 * aleph_0 = aleph_0

aleph_aleph_1 or higher does not exist.

notice that defining what aleph_aleph_1 is the diagonal argument / powerset of is not possible ...

( which is imho required to assume existance of aleph_aleph_1 )

regards

tommy1729
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Messages In This Thread
Tetration of 2 and Aleph_0 - by jht9663 - 09/06/2011, 03:47 PM
RE: Tetration of 2 and Aleph_0 - by JmsNxn - 09/06/2011, 09:28 PM
RE: Tetration of 2 and Aleph_0 - by tommy1729 - 09/07/2011, 03:37 AM
RE: Tetration of 2 and Aleph_0 - by jht9663 - 09/07/2011, 03:33 PM
RE: Tetration of 2 and Aleph_0 - by sheldonison - 09/07/2011, 08:47 PM
RE: Tetration of 2 and Aleph_0 - by sheldonison - 09/09/2011, 05:54 PM
RE: Tetration of 2 and Aleph_0 - by jht9663 - 09/07/2011, 03:34 PM
RE: Tetration of 2 and Aleph_0 - by tommy1729 - 09/10/2011, 12:22 PM
RE: Tetration of 2 and Aleph_0 - by tommy1729 - 11/13/2011, 12:09 PM



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