Generalized arithmetic operator
#2
Well I'm not certain, but your operators seem to be like a modified lower hyperoperators. These operators satisfy the recursion:

\( (x[s]y)[s-1] x = x[s](y+1) \)

where \( x[0]y = x+y \)
Check if this function works. I'm pulling it out of a hat but I have a lot of math behind it.:


\( \frac{2}{x[s]y} = \frac{1}{\Gamma(-s)} \sum_{n=0}^\infty \frac{(-1)^n}{(x[n]y)n!(n-s)} + \sum_{k=0}^\infty \frac{a_k}{\Gamma(k-s+1)} \)

where

\( a_k = \sum_{n=0}^\infty \frac{(-1)^k}{x[n+k]y} \)

This may or may not work. Depending on if 1/x[s]y is holomorphic or meromorphic and if (x[s]y)[s-1]x is holo as well with decent enough behaviour.


Messages In This Thread
Generalized arithmetic operator - by hixidom - 03/11/2014, 03:52 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/11/2014, 03:15 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 06:24 PM
RE: Generalized arithmetic operator - by MphLee - 03/11/2014, 10:49 PM
RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 11:20 PM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 11:18 AM
RE: Generalized arithmetic operator - by JmsNxn - 03/12/2014, 02:59 AM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 04:37 AM
RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 06:19 PM
RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 06:43 PM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:06 AM
RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:42 AM
RE: Generalized arithmetic operator - by hixidom - 06/11/2014, 05:10 PM

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