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 Generalized arithmetic operator hixidom Junior Fellow Posts: 20 Threads: 3 Joined: Feb 2014 03/11/2014, 06:24 PM Quote:$(x[s]y)[s-1]x=x[s](y+1)$ I can't seem to prove or disprove that statement in my system, except by the following discrepancy: Wikipedia has $a[4]b=a^{a^{b-1}}$, which doesn't agree with what I have. For example: According to Wiki, $a[4]4=a^{a^3}$ According to what I have, $a[4]4=[3]^2 a=[3][3]a=[3](a^a)=(a^a)^{(a^a)}$. So I don't think that that recursion relation results in the same set of hyperoperators. Do you think that the equation with the summation still applies? What exactly should I take from that equation? Is it to be evaluated numerically? Thanks for the response. hixidom « Next Oldest | Next Newest »

 Messages In This Thread Generalized arithmetic operator - by hixidom - 03/11/2014, 03:52 AM RE: Generalized arithmetic operator - by JmsNxn - 03/11/2014, 03:15 PM RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 06:24 PM RE: Generalized arithmetic operator - by MphLee - 03/11/2014, 10:49 PM RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 11:20 PM RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 11:18 AM RE: Generalized arithmetic operator - by JmsNxn - 03/12/2014, 02:59 AM RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 04:37 AM RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 06:19 PM RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 06:43 PM RE: Generalized arithmetic operator - by tommy1729 - 03/21/2014, 10:31 PM RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:06 AM RE: Generalized arithmetic operator - by tommy1729 - 03/22/2014, 12:13 AM RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:42 AM RE: Generalized arithmetic operator - by hixidom - 06/11/2014, 05:10 PM

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