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 Generalized arithmetic operator hixidom Junior Fellow Posts: 20 Threads: 3 Joined: Feb 2014 03/12/2014, 04:37 AM I'll try to work with the equation you provided, but it will take me a while to figure it out. Thanks for the suggestion! Regarding the relation provided: $a [x](\alpha + \beta) = (a[x] \alpha)[x-1](a[x] \beta)$ It is only true when $\alpha=\beta$, unfortunately, because $(a[x] \alpha)[x-1](a[x] \beta)\neq(a[x] \beta)[x-1](a[x] \alpha)$ in general. For example (x=4): $(a[4]2)[3](a[4]4)\neq(a[4]4)[3](a[4]2)\leftrightarrow (a^a)^{\left ((a^a)^{(a^a)}\right )}\neq\left ((a^a)^{(a^a)}\right )^{(a^a)$ « Next Oldest | Next Newest »

 Messages In This Thread Generalized arithmetic operator - by hixidom - 03/11/2014, 03:52 AM RE: Generalized arithmetic operator - by JmsNxn - 03/11/2014, 03:15 PM RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 06:24 PM RE: Generalized arithmetic operator - by MphLee - 03/11/2014, 10:49 PM RE: Generalized arithmetic operator - by hixidom - 03/11/2014, 11:20 PM RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 11:18 AM RE: Generalized arithmetic operator - by JmsNxn - 03/12/2014, 02:59 AM RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 04:37 AM RE: Generalized arithmetic operator - by MphLee - 03/12/2014, 06:19 PM RE: Generalized arithmetic operator - by hixidom - 03/12/2014, 06:43 PM RE: Generalized arithmetic operator - by tommy1729 - 03/21/2014, 10:31 PM RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:06 AM RE: Generalized arithmetic operator - by tommy1729 - 03/22/2014, 12:13 AM RE: Generalized arithmetic operator - by hixidom - 03/22/2014, 12:42 AM RE: Generalized arithmetic operator - by hixidom - 06/11/2014, 05:10 PM

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